5x^2=19x*4

Solution for 5x^2=19x*4 equation:

5x^2=19x*4

We move all terms to the left:

5x^2-(19x*4)=0

We add all the numbers together, and all the variables

5x^2-(+19x*4)=0

We get rid of parentheses

5x^2-19x*4=0

Wy multiply elements

5x^2-76x=0

a = 5; b = -76; c = 0;
Δ = b2-4ac
Δ = -762-4·5·0
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-76}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+76}{2*5}=\frac{152}{10}
=15+1/5
$